Tue 18 Mar |
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PrincipleWhat do we do with an opening (12-15HP) and a 5+card in the suit of the enemy opener? PASS! Partner will double protectively as of 8+HP and with 2+card in enemy suit. Also included is a discussion of the possible interpretations of a double (protective, informative, distributive).
Doubles
X in 1st round 2nd pos = Infodouble 4th pos = Protective Double in 2nd round 2nd pos = Sandwich, 12-15(17)HP, 5+card previous enemy suit, negative other enemy suit 4th pos = distributive remaining suits, 8-11HP in 3rd round = distributive (44) remaining suits, 8-11HP Sandwich Sandwich X remark:
Further Bidding
#1: Opening suit without further competition: sandwich by protective double/(1♣) - PASS - (PASS) - X: protective, 8+, 2-3(4)♣ /(PASS) - PASS: sandwich, 12-15HP, 5+♣ - bid: no sandwich #2: Opening suit (2nd man in 2nd position): sandwich by double in 2nd hand/(1♣) - PASS = possibly sandwich - (1♦) - PASS /(1SA2♣) = not outside opening suit; so 2 suits remaining - X = sandwich, 12-15HP, 5+♣, neg ♦ (so 3+♥ 3+♠) - (PASS) - PASS = (1)2+♣ /(1♥) = outside opening suit - X = sandwich, 12-15HP, 5+♣, neg 0(2)♥ (so (3)4-♠) /(1♠) = outside opening suit - X = sandwich, 12-15HP, 5+♣, neg 0(2)♠ (so(3)4-♥) /(2♦) = outside opening suit, fit with answerer's suit - X = sandwich, 12-15HP, 5+♣, neg 0(2)♦ (so 4-3+♥♠) #3: Answerer's suit (4th man in 2nd position): sandwich double in 4th hand/(1♣) - PASS - (1♦) - PASS = possibly sandwich /(1SA2♣) = old suit - PAS - (2♦SA) - X = sandwich, 12-15HP, 5+♦, neg ♣ (so 3+♥ 3+♠) /(1♥) = new suit - PAS - (1SA of 2♦) = repeat of suit first answer - X = sandwich, 12-15HP, 5+♦ - (2♥) = fit 2nd suit opener - X = sandwich, 12-15HP, 5+♦, 0-3♥ #4: In 4th position (2nd man OR 4th man): distributive double/(1♣) - PASS - (1♦) - PAS /(PASS) - X= distributive, 8-11HP, neg ♣♦ (dus ♥♠) /(1SA) - PASS - (PASS) - X= distributive, 8-11HP, neg ♣♦ (dus ♥♠) caution! sandwich double on answerer's suit is impossible in 4th position Distributive X and delayed following bids
1) 8-11HP and 44 in remaining suits, distributive - 1st method: X in 3rd round (see Doubles) (1♣) - PASS - (1♦) - PASS / (1SA or 2♣♦) - 2♥♠ = 5+♥♠ with 1 honor card, 7-11HP if we wouldn't be playing sandwich defense, we could use a normal X in the 2nd round for distribution. Examples/(1♦) - PASS - (1♠) - PAS - (PASS) - X: 8-9HP, 4-♣4-♥ - (2♦♥♠) - X: 12-15(17)HP, 5+♠, neg ♦ = sandwich on answerer's suit / (2♣♦♠) - X: 12-15(17)HP, 5+♦, neg ♠ = sandwich on opening suit / (2♣♦) - PASS - (2♥♠) - X: 12-15(17)HP, 5+♠, neg ♦ = sandwich on answerer's suit in the 3rd round: - X: 8-11HP, 4-♣ 4-♥ / (2♠) - PASS - (PASS) - X: 8-11HP, 4-♣ 4-♥
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| Last Updated on Wednesday, 13 August 2008 21:13 |